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    Thursday, 29 September 2016

    Waec Gce 2016 Physics Practical Answers


    1a )
    xi (cm )| yi (cm )| zi (cm )|W 1(Nx 10^ -2)|W 2 (Nx 10 ^ -2 )|u =(w 1 -w 2)(Nx 10 ^ -2)| v =(w 1 -w 3)(Nx 10 -2)
    =>1 .80 |1 .50 |1 .70 |3 .6| 3. 00| 3. 40| 0. 60|0. 20
    =>3 .80 |3 .00 |3 .00 |7 .6| 6. 00| 6. 00| 1. 60|1. 60
    =>5 .50 |4 .40 |5 .00 |11 .10 | 8.00 | 10. 00 |2. 20 |1. 00
    =>7 .30 |5 .90 |6 .60 |14 .60 | 11. 80 |13 .00 |2. 80 |1. 40
    =>9 .20 |7 .30 |8 .30 |18 .40 | 14. 60 |16 .60 |3. 80 |1. 80
    =>11 .10 | 8.30 | 10. 00 |22 .20 |16 . 60| 20 .00 |5. 60 |2. 20



    1b)Relative density, or specific
    gravity, is the ratio of the
    density (mass of a unit
    volume) of a substance to the
    density of a given reference
    material. Specific gravity
    usually means relative
    density with respect to water.


    1bii) given volume of solid immersed
    Vsi =1/2*30cm³
    =15cm³
    Density of liquid (water)ew= 1g/cm³
    Acceleration due to gravity, g = 10m/s²
    Upthrust, U= eVsi g
    U= 1000*(15*10^-6)*10
    U=15*10-²
    U=0.15N

    Weight of solid =mg
    =EsVs g
    given: Es=2.4g/cm³ (2400kg/m³)
    Vs=30cm (30*10^-6 m³)
    g=10m/s²

    Weight, w=30*10^-6*2400*10
    =72*10-²
    =0.72N
    Reading on spring balance =W-U
    =0.72-0.15
    =0.57N
    ======================





    2bi)-It is used for Magnifying glass:
    For a magnifying glass to work, the object is
    placed at the focal point such that the image
    produced is magnified, upright and virtual.

    - It is used in aSlide projector: a projector essentially uses a
    convex lens to form on a screen a real, magnified
    and inverted image of the slide or film. The slide,
    being the object, is positioned between the j and 2f
    from the lens.
    =====================




    3) | R/n | I(A) |P=E/I V n^-1
    1. |0.00| 3.00 |0.500
    2. |1.00| 1.00.|1.500
    3. |2.00| 0.60 |2.500
    4. |3.00|0.45. |3.333
    5. |4.00|0.35. |4.286
    6. 5.00 |0.25. |6.000

    3vi)
    S=y2-y1/x2-x1
    =4-2/3.6-1.5
    =2/2.1
    =0.952

    3vii) C=0.5ohms

    3Viii)Resitance

    3ix)-I ensured that the circuit is open after each reading to maintain the E.M.F of the battery

    -I ensured that the Zero Error of the Ammeter is checked and noted




    3b)Internal resistance of a cell is the resistance within a
    battery, or other voltage source, that causes a
    drop in the source voltage when there is a
    current. There is, therefore, actual reduction in
    the electromotive force of the cell , as well as an
    increase in internal resistance.
    ======================

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